Email
Chat with tutors
logo

Ask Questions, Get Answers

X
 
Questions  >>  Archives  >>  JEEMAIN-2014
Answer
Comment
Share
Q)

The equation of the normal to the curve $y=x^3-x^2$ at the point $(1,1)$ lying on it is

$\begin{array}{1 1} x+y=0 \\ x-y=0 \\ x+y=-1 \\ x+y=2 \end{array} $

Please log in or register to answer this question.

Home Ask Tuition Questions
Practice
Your payment for is successful.
Continue
...