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Calculate the maximum work done in expanding $16\;g$ of oxygen at $300\;k$ and occupying a volume of $5dm^3$ isothermally until the volume become $25\;dm^3$

$\begin{array}{1 1} 201 \times 10^3\;joule \\ 2.01 \times 10^3\;joule \\ 2.01 \times 10^2\;joule \\2.01 \;joule\end{array} $

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