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JEEMAIN-2014
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The solubility product of silver chlorides is $1.5625 \times 10^{-10}$ at $ 25^{\circ}C$. Find its solubility in $gL^{-1}$
$\begin{array}{1 1} 1.79 \times 10^{-3} gL^{-1} \\ 1.89 \times 10^{-3} gL^{-1} \\ 2 \times 10^{-3} gL^{-1}\\ 2.89 \times 10^{-3} gL^{-1} \end{array} $
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