Q)
Suppose the particle in $Q_{33}$ is an electron projected with velocity $V_x =2.0 \times 10^6 m/s$. If E between the plates separated by $0.5 \;cm$ is $9.1 \times 10^2 N/C$, where will the electron strike the upper plate ? $(|e|=1.6 \times 10^{-19}\;C,m_e=9.1 \times 10^{-3}\;kg)$
1 Answer
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