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Questions  >>  Olympiad-Math  >>  Class 8
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Q)

The value of $(3x^3+9x^2+27x) \div 3x$ is

$\begin{array}{1 1} x^2+9+27x \\ 3x^3+3x^2+27x \\ 3x^3+9x^2+9 \\ x^2+3x+9 \end{array} $

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