Simplify : $\bigg( \large\frac{4}{9}\bigg)^{-2} \times \bigg( \large\frac{1}{4} \bigg)^{-2} \times \large\frac{1}{3^{-2}} \times \bigg( \large\frac{17}{18}\bigg)^0$

Question

$\begin{array}{1 1} 9 \\ 729 \\ \large\frac{1}{729} \\\large \frac{1}{81} \end{array} $