Find the value of x so that $\bigg(\large\frac{5}{3} \bigg)^{-2} \times \bigg(\large\frac{5}{3}\bigg)^{-14} =\bigg(\large\frac{5}{3}\bigg)^{8x}$

Question

$\begin{array}{1 1} x=2 \\ x=-2 \\ x=4 \\ x=5 \end{array} $