Given the resistance of $1 \Omega, 2 \Omega,3 \Omega$ how will you combine thus to get , an equivalent resistance of $(i) \large\frac{11}{3}$$\Omega \qquad (ii) \large\frac{6}{11}$$\Omega \qquad (iii) \large\frac{11}{5}$$\Omega \qquad (iv) 6 \Omega?$

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