Determine the current though the battery of internal resistance $0.5 \Omega$ for the circuit as shown in the figure. How much power is distributed in $6 \Omega$ resistance ?

Question

$\begin{array}{1 1} 33.8\;w \\ 3.38\;w \\ 0.338\;w \\ 338\;w \end{array}$

Comments

But total one ampere curret is not flowing through BE .so how we can i*2R ??