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Questions  >>  CBSE XII  >>  Physics  >>  Magnetism and matter
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A closely wound solenoid of $2000$ turns and area of cross section $1.6 \times 10^{-4}m^2$, carrying a current of $4.0\;A$ is suspended through its center allowing it to turn in a horizontal plane. What are the force and torque on the solenoid, if a uniform horizontal magnetic field of $7.5 \times 10^{-2}\;T$ is setup at an angle of $30^{\circ}$ with the axis of solenoid ?

$\begin{array}{1 1} 4.8 \times 10^{-2}\;N-m \\ 4.8 \times 10^{-2}\;N-m \\ 4.8 \times 10^{2}\;N-m \\ 4.8 \times 10^{2}\;N-m \end{array} $

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