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Questions  >>  CBSE XII  >>  Physics  >>  Magnetism and matter
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A magnetic needle of magnetic moment $4.8 \times 10^{-2}\;JT^{-1}$ is placed at $30^{\circ}$ with the direction of uniform magnetic field of magnitude $3 \times 10^{-2} \;T$ Calculate the torque acting on the needle

$\begin{array}{1 1} 7.2 \times 10^{-4}J \\ 7.2 \times 10^{-4}JT^{-1} \\ 7.2 \times 10^{4}J \\ 7.2 \times 10^{4}JT^{-1} \end{array} $

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