A circular coil of $30$ turns and radius $8.0 \;cm$ carrying a current of $6.0 \;A$ is suspended vertically in a uniform horizontal magnetic field of magnitude $1.0 \;T$.The field lines makes an angle of $60^{\circ}$ with the normal of the coil. Calculate the magnetic of the counter torque that must be applied to prevent the coil from turning .

Question

$\begin{array}{1 1} 3.133\;N/m \\ 3.133\;N-m \\ 3.133\;N/m^2 \\ 3.133\;N/m^2 \end{array}$