$\begin{array}{1 1} \text{$-1.8 \times 10^{-2} N-m$, anticlock with negative x- direction } \\ \text{$-1.8 \times 10^{-2} N-m,$ along positive y- direction } \\ \text{$T=-1.80 \times 10^{-2} \hat j N-m,$ along negative z- direction } \\ \text{$T=-2.80 \times 10^{-2} \hat j N-m,$ along negative y- direction } \end{array} $