Three coins are tossed. What is the probability of getting at most two tails?

Question

( A ) \large\frac{1}{8}
( B ) \large\frac{1}{7}
( C ) \large\frac{7}{8}
( D ) \large\frac{1}{2}

Comments

Total possible outcomes= (HHH, HHT, HTH, THH, HTT, THT, TTH, TTT)
E=(HHT,HTH,THH,HTT,THT,TTH)
n(E)=6
Total no of outcomes= 8
P(E)= 6/8 = 3/4