$0.002$ molar solution of Nacl having degree of dissociation of $90\%$ at $27^{\circ}C$ has osmotic pressures equal to :

Question

$\begin{array}{1 1} 0.94\;bar \\ 9.4\;bar \\ 0.094\;bar \\ 9.4 \times 10^{-4}\;bar \end{array}$