The half - cell reaction for the corrosion $2H^++frac{1}{2}O_2+2e^{-}\to H_2O ; \in^0=1.23\;V \\ Fe^{2+}+2e^{-} \to Fe_{r} ; \in^0=-0.44\;V$

Question

$\begin{array}{1 1} -76\;KJ \\ -322\;Kg \\ -161\;KJ \\ -152\;KJ \end{array} $