The electrode reaction takes place at the anode of $CH_2 -O_2$ fuel cell is

Question

$\begin{array}{1 1} 2O_2+2H^+ +8e^- \to 4H_2O \\ CH_4 +2H_2O \to CO_2 +8H^+ +8e^{-} \\ CH_4 +2O_2 \to CO_2 +2H_2O \\ 2H^+ +2e^{-} \to H_2 \end{array}$