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JEEMAIN-2015
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Q)
The distance, from the origin, of the normal to the curve, $x= 2 \cos t +2 t \sin t; y=2 \sin t- 2t \cos t 2t $ at $t= \large\frac{\pi}{4}$ is :
$\begin{array}{1 1} 4 \\ 2\sqrt 2 \\ 2 \\ \sqrt 2 \end{array} $
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