$\begin{array}{1 1} 4 \bigg(\frac{x+1}{x-2} \bigg)^{1/4} +c \\4\bigg(\frac{x-2}{x+1} \bigg)^{1/4} +c \\ \frac{-4}{3}\bigg(\frac{x+1}{x-2} \bigg)^{1/4} +c \\ \frac{-4}{3} \bigg(\frac{x-2}{x+1} \bigg)^{1/4} +c \end{array} $