For the LCR circuit , shown here , the current is observed to lead the applied voltage. An additional capacitor C', when joined with the capacitor C present in the circuit , makes the power factor of the circuit unity. The capacitor C', must have been connected in :

Question

$\begin{array}{1 1} \text{series with C and has a magnitude } \frac{1- \omega^2LC}{\omega^2 L} \\\text{series with C and has a magnitude } \frac{C}{(\omega^2 LC-1)} \\ \text{Parallel with C and has a magnitude } \frac{C}{(\omega^2 LC-1)} \\\text{parallel with C and has a magnitude } \frac{1- \omega^2 L C}{\omega^2 L} \end{array}$