For the equilibrium, $A(g) \to B(g), \Delta H$ is $-40\;kJ/mol$. If the ratio of the activation energies of the forward $(E_f)$ and reverse $(E_b)$ reaction is $ \large\frac{2}{3}$ then

Question

$\begin{array}{1 1} E_f= 60\;kJ/mol; E_b=100\;kJ/mol \\ E_f= 30\;kJ/mol; E_b=70\;kJ/mol\\ E_f= 80\;kJ/mol; E_b=120\;kJ/mol \\ E_f= 70\;kJ/mol; E_b=30\;kJ/mol \end{array} $