If the two roots of the equation, $(a-1)(x^4+x^2+1)+(a+1)(x^2+x+1)^2=0$ are real and distinct , then the set of all values of 'a' is :

Question

$\begin{array}{1 1} \bigg(\frac{-1}{2},0 \bigg) \\ (-\infty,-2) \cup (2,\infty) \\ \bigg(\frac{-1}{2},0 \bigg) \cup \bigg(0,\frac{1}{2}\bigg) \\ \bigg(0,\frac{1}{2}\bigg) \end{array} $