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Questions  >>  Archives  >>  JEEMAIN-2015
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The equation of a normal to the curve , $\sin y = x \sin \bigg( \large\frac{\pi}{3}+y\bigg)$ at $x=0$ is

$\begin{array}{1 1} 2x+\sqrt 3 y =0 \\ 2y-\sqrt 3 x =0 \\ 2y+\sqrt 3 x =0 \\ 2x-\sqrt 3 y =0 \end{array} $

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