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If 2 identical balls are to be placed in 3 identical boxes, then the probability that one of the boxes contains exactly 3 balls is :

$\begin{array}{1 1} \frac{55}{3} \bigg(\frac{2}{3}\bigg)^{11} \\ 55 \bigg(\frac{2}{3} \bigg)^{10} \\ 220 \bigg(\frac{1} {3}\bigg)^{12} \\ 22 \bigg(\frac{1}{3} \bigg)^{11} \end{array} $

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