If $12$ identical balls are to be placed in 3 identical boxes, then the probability that one of the boxes contains exactly 3 balls is:

Question

$\begin{array}{1 1} 55 \bigg( \frac{2}{3}\bigg)^{10} \\ 220 \bigg( \frac{1}{3}\bigg)^{12} \\ 22 \bigg( \frac{1}{3}\bigg)^{11} \\ \frac{55}{3} \bigg( \frac{2}{3}\bigg)^{11} \end{array} $