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The integral $\int \frac{dx}{x^2(x^4+1)^{3/4}}$ equals :

$\begin{array}{1 1} -\bigg(\frac{x^4+1}{x^4}\bigg)^{1/4}+c \\ \bigg(\frac{x^4+1}{x^4} \bigg)+c \\ (x^4+1)^{1/4}+c \\ -(x^4+1)^{1/4}+c \end{array} $

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