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Questions  >>  Archives  >>  JEEMAIN-2015
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The equation of the plane containing the line $2x-5y+z=3; x+y+4z=5$ and parallel to the plane , $x+3y+6z=1$, is :

$\begin{array}{1 1} 2x+6y+12z=-13 \\ 2x+6y+12z=13 \\ x+3y+6z=-7 \\ x+3y+6z=7 \end{array} $

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