
$\begin{array}{1 1} \sqrt{\frac{\pi \lambda gL}{\mu_0}\tan \theta} \\ \sin \theta \sqrt { \frac{\pi \lambda gL}{\mu_0 \cos \theta}} \\ 2 \sin \theta \sqrt{\frac{\pi \lambda gL}{\mu_0 \cos \theta}} \\ 2 \sqrt {\frac{\pi gL}{\mu_0} \tan \theta} \end{array} $