The solution of $\large\frac{6x}{4x-1} < \frac{1}{2}$ is

Question

$\begin{array}{1 1} x < \large\frac{-1}{8} \\ \large\frac{-1}{8} < x < \frac{1}{4} \\ x < \large\frac{-1}{8} \;and \; x > \large\frac{1}{4} \\ x > \large\frac{1}{8} \end{array}$