Equation of a line passing through $(-1,2,-3)$ and perpendicular to the place $2x+3y+z+5=0$ is

Question

$\begin{array}{1 1} \frac{(x-1)}{-1}= \frac{y+2}{1} =\frac{z-3}{-1} \\ \frac{(x+1)}{-1}= \frac{y-2}{1} =\frac{z+3}{1} \\ \frac{(x+1)}{2}= \frac{y-2}{3} =\frac{z+3}{1} \\ \frac{(x+1)}{1}= \frac{y+2}{-2} =\frac{z+3}{8} \end{array}$