# Two vertices of an equilateral triangle are $(-1,0) (1,0)$ qand the third vertex lies above the x -axis . Then the equation of the circum circle is
$\begin{array}{1 1} x^2-y^2+\frac{2y}{\sqrt 3} +1=0 \\ x^2+y^2 - \frac{2y}{\sqrt 3} -1=0 \\ x^2-y^2-\frac{y}{\sqrt 3} =0 \\ None\;of\;these \end{array}$