In an AC circuit V and I are given by $V=100 \sin (100 t) volt \; I =100 \sin (100 t +\large\frac{\pi}{3})amp$ the power dissipated in the circuit is

Question

$\begin{array}{1 1} 10^4\;W \\ 2.5\;KW \\ 5 KW \\ 10 W \end{array}$