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Questions  >>  CBSE XII  >>  Physics  >>  Wave optics
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Wave length of light used in an optical instrument are $ \lambda_1=4000^{\circ}A$ and $ \lambda_2=5000^{\circ}A$ then ratio of their respective resolving power .(corresponding to $\lambda_1$ and $\lambda_2$) is

$\begin{array}{1 1} 16:25 \\ 9:1 \\ 4:5 \\ 5:4 \end{array} $

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