An election micro scope uses electrons accelerated by a voltage of 50 kv. Determined the de-Broglie wave length associated with the electrons. If other factor (such as numerical aperture ) are taken to be roughly the same, how does the resolving power of an electron microscope that uses yellow light ?

Question

$\begin{array}{1 1} \lambda= 5.5 \times 10^{-12}\;m ;\text{R.p of an microscope about} 10^6 \text{times that of an optical microscope } \\ \lambda= 5.5 \times 10^{-10}\;m ;\text{R.p of an microscope about} 10^5 \text{times of an optical microscope } \\ \lambda= 5.5 \times 10^{-12}\;m ;\text{R.p of an microscope about} 10^5 \text{times that of an optical microscope } \\ \lambda= 5.5 \times 10^{-10}\;m ;\text{R.p of an electron microscope is about} 10^6 \text{times that of an optical microscope } \end{array}$