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CBSE XII
>>
Physics
>>
Nuclei
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Q)
Given
m
(
86
R
220
n
=
220.1137
u
;
m
(
84
P
o
216
)
=
216.00189
u
and
m
α
=
4.00260
u
Find the Q value and K.E of the emitted
α
particle in the
α
decay of
86
R
n
220
Q
=
6.41
M
e
v
,
K
.
E
=
6.29
M
e
v
Q
=
48.5
M
e
v
,
K
.
E
=
49.4
M
e
v
Q
=
4.94
M
e
v
,
K
.
E
=
4.85
M
e
v
Q
=
4.85
M
e
v
,
K
.
E
=
48.5
M
e
v
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