The radio nuclide $_6C^{11}$ decays according to $_6C^{11} \to _5B^{11}+e^++\gamma$ half life $=20.3\;min$ The maximum energy of the emitted position is $0.960\;Mev$ given the mass values $m(_6C^{11})=11.011434 \;u\;m (_6B^{11})=11.009305$ calculate Q and compare it with maximum energy of position emitted .

Question

$\begin{array}{1 1} 9.61\;Mev \\ 96.1 \;Mev \\ 0.961\;Mev \\ 0.0961\;Mev \end{array} $