Suppose that the electric field amplitude of an electromagnetic wave is $E_0 = 120 N/C$ and its frequency is $\gamma = 50.0 \;MHz$ . Find the expression of $\overrightarrow{E}$ and $\overrightarrow{B}$

Question

$\begin{array}{1 1} (i) E= (120 N/c) \sin [(1.05 rad/m)x-3.14 \times 10^8 rad/sec] \hat i, B = (4 \times 10^{-7} T) \sin [(1.05 rad /m)x - 3.14 \times 10^8 \;rad/sec] \hat j \\ (i) E= (120 N/c) \sin [(1.05 rad/m)x-3.14 \times 10^8 rad/sec] \hat j, B = (4 \times 10^{-7} T) \sin [(1.05 rad /m)x - 3.14 \times 10^8 \;rad/sec] \hat k \\ (i) E= (120 N/c) \sin [(1.05 rad/m)x-3.14 \times 10^8 rad/sec] \hat k, B = (120\;N/c) \sin [(1.05 rad /m)x - 3.14 \times 10^8 \;rad/sec] \hat i \\ (i) E= (120 N/c) \sin [(1.05 rad/m)x-3.14 \times 10^8 rad/sec] \hat j, B = (120 N/C) \sin [(1.05 rad /m)x - 3.14 \times 10^8 \;rad/sec] \hat j \end{array}$