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CBSE XII
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Physics
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Alternating current
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A $60 \mu F$ capacitor is connected to a $110\;v,60\;Hz$ a.c supply what is the net power absorbed by reach circuit over a completed cycle ? explain your answer
$\begin{array}{1 1} 0 \\ E_vI_v \\ \large\frac{E_v}{I_v} \\ \large\frac{I_v}{E_v} \end{array} $
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