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Questions  >>  CBSE XII  >>  Math  >>  Matrices
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Using elementary row transformation, find the inverse of $A = \begin{bmatrix} 2 & -6 \\ 1 & -2\end{bmatrix}$


$(A)\;A^{-1} = \begin{bmatrix} -1 & -3 \\ -\frac{1}{2} & -1 \end{bmatrix}$
$ (B)\; A^{-1} = \begin{bmatrix} -1 & 3 \\ \frac{1}{2} & 1 \end{bmatrix}$
$ (C)\; A^{-1} = \begin{bmatrix} 1 & 3 \\ \frac{1}{2} & 1 \end{bmatrix}$
$ (D)\; A^{-1} = \begin{bmatrix} -1 & 3 \\ -\frac{1}{2} & 1 \end{bmatrix}$

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