# Solve the differential equation $\frac{dy}{dx} = log (x+1)$
$(A)\; y = (x+1)\; log (x+1) - x - C$
$(B)\; y = (x+1)\; log (x+1) +x - C$
$(C)\; y = (x+1)\; log (x+1) - x + C$
$(D)\; y = (x+1)\; log (x+1) + x + C$