Q)
Decomposition of phosphine (PH3) at 120∘C proceeds according to the equation: 4PH3(g)→P4(g)+6H2(g) It is found that this reaction follows the following rate equation: Rate =k[PH3] The half-life of PH3 is 37.9s at 120∘C. (i) How much time will be required for 34 of PH3 to decompose? (ii) What fraction of the original amount of PH3 will remain undecomposed after 1 minute?
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