A, B and C are three complexes of Chromioum with the empirical formula $H_{12}O_{6}Cl_3Cr$. All the three complexes have $Cl$ and $H_2O$ molecules as the ligands. Complex A does not react with conc. $H_2SO_4$. Complexes $B$ and $C$ lose $6.75\%$ and $13.5\%$ of their original weight respectively on heating with conc. $H_2SO_4$. Identify A, B and C.

Question

$\begin{array}{1 1} (a)\;A=[Cr(H_2O)_6] , B=[Cr(H_2O)_5Cl]Cl_2.H_2O , C = [Cr(H_2O)_4Cl_2]Cl.2H_2O \\ (b)\;A=[Cr(H_2O)_3]Cl_3 , B=[Cr(H_2O)_2Cl]Cl_2.H_2O , C = [Cr(H_2O)_4Cl_2]Cl \\ (c)\;A=[Cr(H_2O)_6]Cl_3 , B=[Cr(H_2O)_5Cl]Cl_2.H_2O , C = [Cr(H_2O)_4Cl_2]Cl.2H_2O \\(d)\;A=[Cr(H_2O)_6]Cl_3 , B=[Cr(H_2O)_5Cl]Cl_2 , C = [Cr(H_2O)_4Cl_2]Cl\end{array}$