Figure shows two identical capacitors $C_1$ and $C_2$ , each of $2 \mu F$ capacitance , connected to a battery of $5\;V$ . initially switch 'S' is closed . After some times S is left open and dielectric slabs of dielectric constant $K=5$ are inserted to fill completely the space between the plates of the two capacitors . How will the charge and potential difference between the plates of the capacitors be affected after the slab are inserted ?

Question

$\begin{array}{1 1} 10\;V \\ 2\;V \\ 3\;V \\ 1\;V \end{array}$