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In the Hofmann bromamide degradation reaction, the number of moles of $NaOH$ and $Br_2$ used per mole of amine produced are :

$\begin{array}{1 1} \text{(1) One mole of NaOH and one mole of} Br_2 \\(2) \text{Four moles of NaOH and two moles of} Br_2 \\ (3) \text{Two moles of NaOH and two moles of} Br_2 \\(4) \text{Four moles of NaOH and one mole of} Br_2 \end{array} $

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