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A wire of length $2$ units is cut into two parts which are bent respectively to form a square of side = x units and a circle of radius = r units. If the sum of the areas of the square and the circle so formed is minimum, then:

$\begin{array}{1 1}(1)2x=(\pi=4)r \\ (2)(4 \pi) x= \pi r \\ (3)x=2r \\ (4)2x=r \end{array} $

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