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JEEMAIN-2013
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Q)
Let
[
∈
0
]
denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = Time and A = electric current, then:
(
1
)
[
∈
0
]
=
[
M
−
1
L
−
3
T
2
A
]
(
2
)
[
∈
0
]
=
[
M
−
1
L
−
3
T
4
A
−
2
]
(
3
)
[
∈
0
]
=
[
M
−
1
L
2
T
−
1
A
−
2
]
(
4
)
[
∈
]
=
[
M
−
1
L
2
T
−
1
A
]
Share
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