If the lines $\large\frac{x-2}{1} =\frac{y-3}{1} =\frac{z-4}{-k}$ and $\large\frac{x-1}{k} =\frac{y-4}{2} =\frac{z-5}{1}$ are coplanar, then k can have :

Question

$\begin{array}{1 1}\text{(1) any value} \\ \text{(2) exactly one value} \\ \text{(3) exactly two values } \\ \text{(4) exactly three values } \end {array}$