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The equation of the circle passing through the foci of the ellipse $\large\frac{x^2}{16}+\frac{y^2}{9} $$=1$ and having center at $(0,3)$ is :

$\begin{array}{1 1} (1) x^2+y^2-6y -7 =0 \\(2) x^2+y^2-6y+7=0 \\ (3) x^2+y^2-6y-5=0 \\ (4) x^2+y^2-6y+5=0 \end {array}$

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