A carnot freezer takes heat from water at $0^oC$ inside it and rejects it to the room at a temperature of $27^oC$. The latent heat of ice is $336 \times 10^3 J kg^{-1}$. The latent heat of ice is $336 \times 10^3 J kg$. If $5 kg$ of water at $ 0^oC $ is converted into ice at $0^oC$ by the freezer, then the energy consumed by the freezer is close to :

Question

$\begin{array}{1 1}(1) 1.68 \times 10^6 J \\ (2) 1.71 \times 10^7J \\ (3) 1.51 \times 10^5 J\\ (4) 1.67 \times 10^5 J \end{array} $