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Identify the correct trend given below : (Atomic No.= $Ti : 22, Cr : 24$ and $Mo : 42$)

$\begin{array}{1 1}(1) \Delta 0 \;of\; [Cr(H_2O)_6]^{2+} > [Mo(H_2O)_6 ^{2+} \;and\; \Delta 0 \;of\; [Ti(H_2O)_6]^{3+} > [Ti (H_2O)_6]^{2+}\\ (2) \Delta 0 \;of\; [Cr(H_2O)_6]^{2+} > [Mo(H_2O)_6 ^{2+} \;and\; \Delta 0 \;of\; [Ti(H_2O)_6]^{3+} < [Ti (H_2O)_6]^{2+} \\ (3) \Delta 0 \;of\; [Cr(H_2O)_6]^{2+} < [Mo(H_2O)_6 ^{2+} \;and\; \Delta 0 \;of\; [Ti(H_2O)_6]^{3+} > [Ti (H_2O)_6]^{2+} \\ (4) \Delta 0 \;of\; [Cr(H_2O)_6]^{2+} < [Mo(H_2O)_6 ^{2+} \;and\; \Delta 0 \;of\; [Ti(H_2O)_6]^{3+} < [Ti (H_2O)_6]^{2+} \end{array} $

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